Ok, I’ll try to answer your questions somewhat in order.
EPO Procedure Step 1
I’m not quite sure why your asking this question, but let me try to answer it. Let’s assume you had some chemistry in high school. There your would have probably learned about the concept of recrystallization. Basically you dissolve the substance, salt it out of solution, filter, dissolve, salt, filter, … Usually done by controlling temperature (steam bath – ice bath). Each cycle of the process yields a more pure sample (retentate). As a matter of fact, retentate simply means the stuff retained, or left on the filter. You simply continue cycling the process until the desired level of purity is achieve.
The same concept applies to the “retentate” in the EPO test. It’s just that instead of using solubility to differentiate the compound of interest from the contaminants, you’re using molecular weight. In addition, instead of using temperature, your using centrifugal force. Notwithstanding, based on the design of the experiment (DOE), the object would be the opposite. Instead of removing contaminants, you would be introducing one, specifically rEPO.
Spiking the retentate
Now, based on the above, it doesn’t really matter when you spike. You could spike an alloquat of urine, then purify, or you can purify, spike, and re-purify. What’s important here is that you first know the concentration of rEPO in the sample. You can determine this by purifying a different alloquat of sample, or working with the one you have. However, if you only have one sample (alloquat), then you would have to start with the retentate. What’s important here, based on the DOE, is that there is no “contaminant” (rEPO) in the original sample. Although, valid results can be obtained using samples already containing the “contaminant” it makes the entire process much more difficult.
Sample Size
According to Ashenden (
http://nyvelocity.com/content/features/2009/spiking-armstrongs-99-samples) the original sample size was about 125ml. From that 20ml aliquots were taken, and I assume the rest was disgarded. One aliquot was tested in 99, the A Sample. The second aliquot (B Sample) was store for future reference. So, for this study, the whole sample would be 20 ml. I would guess that the reason they shoe 20ml was it provided enough sample for testing, on average, and it was a small enough to store efficiently.
Surviving Isoforms
This is the point of a recovery study. Filtration methods are normally prone to loss, which we’ll call mechanical loss. In addition, there are issues with protein binding, and degradation and other things. First, step is to identify if they is loss, then the second step is to identify where. If it’s mechanical loss, you look to modify the method. Note. that I believe this type of filtration is less prone to loss than you would see from a recrystallization process, but thinking is not the same as knowing.
In closing, let me apologize if you feel that I’m being pedantic or condescending, I don’t mean to be either. It’s just that I’m not sure how familiar you are with the subject matter, so I’m taking it slow. More to follow.