- Jul 2, 2009
- 3,406
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- 13,485
- Mar 16, 2009
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- 2
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I think constricting anus 100 times and denting navel 100 times in succession everyday is effective to good-bye depression and take back youth. You can do so at a boring meeting or in a subway. If you don't know concentration which gives you peculiar pleasure, your life looks like a hell.
- Mar 16, 2009
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Shizo Kanakuri disappeared while running the marathon in the 1912 Summer Olympics in Stockholm. He was listed as a missing person in Sweden for 50 years — until a journalist found him living placidly in southern Japan.
Overcome with heat during the race, he had stopped at a garden party to drink orange juice, stayed for an hour, then took a train to a hotel and sailed home the next day, too ashamed to tell anyone he was leaving.
There’s a happy ending: In 1966 Kanakuri accepted an invitation to return to Stockholm and complete his run. His final time was 54 years, 8 months, 6 days, 8 hours, 32 minutes and 20.3 seconds — surely a record that will never be broken.
Overcome with heat during the race, he had stopped at a garden party to drink orange juice, stayed for an hour, then took a train to a hotel and sailed home the next day, too ashamed to tell anyone he was leaving.
There’s a happy ending: In 1966 Kanakuri accepted an invitation to return to Stockholm and complete his run. His final time was 54 years, 8 months, 6 days, 8 hours, 32 minutes and 20.3 seconds — surely a record that will never be broken.
- May 18, 2009
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http://www.sun-sentinel2.com/features/ftlaudNEISS/ftlaudNEISS08_list.php?orderby=anarrative
Do some searches. Fun for the whole family!
Do some searches. Fun for the whole family!
- Mar 16, 2009
- 19,482
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MAXIMUM COMMON SUBGRAPH
* INSTANCE: Graphs $G_1=\left(V_1,E_1\right)$ and $G_2=\left(V_2,E_2\right)$.
* SOLUTION: A common subgraph, i.e. subsets ${E_1}'\subseteq E_1$ and ${E_2}'\subseteq E_2$ such that the two subgraphs $G_1'=\left(V_1,{E_1}'\right)$ and $G_2'=\left(V_2,{E_2}'\right)$ are isomorphic.
* MEASURE: Cardinality of the common subgraph, i.e., $\vert E'\vert$.
* INSTANCE: Graphs $G_1=\left(V_1,E_1\right)$ and $G_2=\left(V_2,E_2\right)$.
* SOLUTION: A common subgraph, i.e. subsets ${E_1}'\subseteq E_1$ and ${E_2}'\subseteq E_2$ such that the two subgraphs $G_1'=\left(V_1,{E_1}'\right)$ and $G_2'=\left(V_2,{E_2}'\right)$ are isomorphic.
* MEASURE: Cardinality of the common subgraph, i.e., $\vert E'\vert$.
since moving to china this thread has become one of anguish for me, as I can no longer see the pictures as most of the websites you are getting them from are banned... but I can still see the damned discussions...
- Aug 13, 2009
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