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So there has to be a factor. It looks like they picked the highest factor and the highest weight as well.
Thanks again for the answer.ScienceIsCool said:Escarabajo said:Thanks for the answer.
To the bolded. Is that possible with power meters today? do some power meter have this capability?
The integration of the Torque times the angular velocity is what gives me power which equivalent to the summation. In that case we would not need a correction factor if well calibrated, right?
To the best of my knowledge, no power meter on the market samples angular velocity more than once or twice per revolution - so no integration and therefore some inaccuracy. To add an encoder would definitely add cost, weight, complexity as well as demand more computing resources which is probably why nobody does it. As it is right now, it can be a bit of an effort to stuff a device full of strain gauges and get meaningful data. Then you have to deal with things like vibration, temperature drift, calibration, etc, etc. Oh, and try to get the cost down to a couple hundred bucks so you can make a living at it.
Of course, this doesn't mean current power meters are useless even if they are inaccurate. Taking large time-based samples allows you to average out the data and get a pretty good picture of performance - which is why Froome *really* hates that the Ventoux data got out into the wild. Talk inaccuracies and 6% errors all you want, there's more than enough data to get a good picture of how well he's riding. And when you back that up with different methods (a la Vayer, Ferrari et al) you can have a lot of confidence in your conclusions.
Which is why Sky's "release of data" is just so much bullsh!t. Instead of feeding us the conclusions, hand over the raw data. It'll pretty much confirm that he did 6.1+ W/kg so we'll never see it.
John Swanson
So there has to be a factor. It looks like they picked the highest factor and the highest weight as well.