In real racing situations, the swings are not significant, though.
Take a situation where you have the two groups, group 1 (g1) ahead of group 2 (g2), riding at a constant speed u. At a distance D1, the time gap is of size T1. When g2 passes D1, both groups increase their speed to a constant speed v. Let D2 be the position of g1 when g2 is at D1. Define r=D2-D1.
Then the second split is going to be equal to the first split minus the difference in times, that is;
T2=T1-(time for g1 to travel between D1 and D2)+(time for g2 to travel between D1 and D2)
Because g1 rode at a speed u between the points and g2 rode at speed v, their times to ride between D1 and D2 are r/u and r/v respectively.
So, we see that;
T2=T1-r/u+r/v
T2=T1-(rv/uv-ru/uv) (note that r/v=ru/uv and r/u=rv/uv)
T2=T1-r*(v-u)/uv
Now if we say that a "dramatic" reduction is the time gap halving, then T2=0.5*T1, so;
0.5*T1=T1-r*(v-u)/uv
2r*(v-u)/uv=T1
Now since this is a theoretically flat stage, let's go into the real world and say that u=40km/h, and the sprinters' teams are looking for the stage, so have kept the break in check all day, with the gap at about 6 minutes (or 0.1h). Then the break is 4km up the road, to r=4km. So, plugging it all in,
2*4km*(v-40km/h)/(v*40km/h)=0.1h
8km*(v-40km/h)=v*40km/h*0.1h
8km*v-320kmkm/h=4km*v (cancel one km term)
8v-320km/h=4v
4v=320km/h
v=80km/h
There you have it - in a real world situation, the half the time gap that much that quickly, the speed has to hit 80km/h.
Sorry about all the maths.