Since you didn't address my comment above about "negative power" (as calculated and shown on those polar plots above) not actually corresponding to "power lost", I figured I'd encourage everyone to do a little thought experiment:
Imagine a set of cranks attached to a frictionless bottom bracket, and with a mass attached to each pedal spindle equivalent to the mass of a typical leg. This system is in a gravitational field. When the crank is statically placed in various positions around the crank cycle, what happens? It would stay in whatever position it is placed, right?
Why? Because the force on one side causing a torque about the BB is balanced by a torque in the opposite direction caused by the force on the other mass.
Now, take that system and spin it up to a certain rotational velocity and let it go. What happens now? It continues to spin, correct? Why? Again, because the masses are balanced AND coupled through the crankarms. In other words, no energy is leaving the system, and thus no power is "lost". As one mass rises, it is balanced by the descending mass on the opposite side...and then they "trade off" as the cranks continue to rotate. Think of it as a "circular pendulum" of sorts
However, lets assume that the crankarms have a way of measuring torque built into them and we define "positive power" as torque in the direction of rotation multiplied by the angular velocity, and "negative power" as torque in the opposite direction of the rotation times the angular velocity. That's what those polar plots you show above assume, correct? But, does that "negative power" really mean that power is lost? No, it's an artifact of the rising mass balancing the descending mass and the definition of the term chosen.
So, from the above, it's fairly obvious that as long as one isn't actively pushing back on the rising leg, it's actually OK to have forces that result in what that device would call "negative power". In fact, up to the forces which represent the mass of the leg being risen, it's most likely preferred to have them since it allows your stronger and more efficient pushing muscles to do the job of propelling you forward. The rising leg is actually lifted merely by the descending mass of the falling leg. That saves your hip flexors for the run as well, if you're a triathlete.
So, once again, attempting to reduce "negative power" in a pedal stroke does NOT result in a reduction of "lost power", since none is lost from that mechanism in a balanced, coupled system anyway.
People tend to think of pedaling and individual legs in isolation...hence the popularity of things like single-leg drills, Spinscan, and the like. But, you pedal with BOTH legs AND their masses are coupled through the crank. That changes things...a lot.